4(x^2+19x+70)=544

Solution for 4(x^2+19x+70)=544 equation:

4(x^2+19x+70)=544

We move all terms to the left:

4(x^2+19x+70)-(544)=0

We multiply parentheses

4x^2+76x+280-544=0

We add all the numbers together, and all the variables

4x^2+76x-264=0

a = 4; b = 76; c = -264;
Δ = b2-4ac
Δ = 762-4·4·(-264)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-100}{2*4}=\frac{-176}{8}
=-22
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+100}{2*4}=\frac{24}{8}
=3
$